# The problem of ten divided by three [duplicate]

Possible Duplicate:
Does .99999… = 1?

if 10/3 = 3.33333... (series)

why doesn't 3.333... * 3 = 10 it can never be 10 it's always almost 10 or 9.9999... (infinity)

I have read about this but then no one has an answer yet we all accept the fact that it is true when the statement is fundamentally false.

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## marked as duplicate by Ross Millikan, 5PM, Ittay Weiss, Micah, Ayman HouriehJan 24 '13 at 22:34

$10=9.9999999...$ –  Amr Jan 24 '13 at 21:21
(Abstract) duplicate of Does .99999… = 1? –  Zev Chonoles Jan 24 '13 at 21:22
I smell a troll... –  Mike Jan 24 '13 at 21:34
@Val either you are trolling or you arent comprehending what infinity is. Subtract 9.9999... from 10. What happens? Lets see. $10-9.9=0.1$, $10-9.99=0.01$,... $10-9.999...999=0.000....001$ to infinity $\Rightarrow 10-9.9999...=0.00...$. The 1 never appears! Therefore, $10-9.999...=0 \Rightarrow 10=9.999....$ –  CBenni Jan 24 '13 at 21:47
@Val and Indeed, there are theories of mathematics (particularly hyperreal numbers) where 9.999... is INFINITESMALY smaller than 10. Which means, the difference is smaller than any real number. What we mean when we say $10=9.9999...$ is $St(10)=St(9.\overline{9})$ –  CBenni Jan 24 '13 at 21:50

When we say that $\frac{10}{3} = 3.333\dots$

We have it like this:

$$\text{Let } p = 3.3333\dots$$

$$10p = 33.33333 \dots$$ or

$$9p = 30$$ or

$$p = \frac{30}{9} = \frac{10}{3}$$ That's how I've always convinced myself of the proof. :|

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I believe since we can't never have truly 0 (nothing), something must give way, e.g: 3.3333 * 3.00000=10 maybe because 0 may not mean absolutely 0 if that makes sense? there must be one point on the serious where something must give way? –  Val Jan 24 '13 at 21:32

$10/3=3.\overline{3}$

$3\cdot 3.\overline{3}=9.\overline{9}=9+\dfrac{9}{9}=10$

If $9.9999...$ and $10$ are not the same number, then name a number between them.