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Is this sentence true or false? I'll be glad for some explaination

L is not context-free, then its reverse is also not context-free

Thanks in advance

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The reverse of context-free is also context-free, moreover reverse$^2$ is identity, so $rev(L) \in CFL$ would imply $L = rev(rev(L)) \in CFL$. –  dtldarek Jan 24 '13 at 10:34
OK I got it, thanks :) –  DanielY Jan 24 '13 at 10:35

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