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Is there a name of this trigonometric identity: $$\cos(a+b) \cos(a+c+b) \equiv \frac{1}{2} \left[\cos(c) + \cos(2a+2b+c) \right]$$

Bsaically we are "changing" a product of cosines into a sum of cosines.

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Product-to-sum identity? – Fabian Jan 23 '13 at 20:33

This is a result of angle sum and difference identities.

$\cos(a+b) = \cos(a)\cos(b)-\sin(a)\sin(b)$

$\cos(a-b) = \cos(a)\cos(b)+\sin(a)\sin(b)$


$\cos(a)\cos(b) = \frac{1}{2}(\cos(a+b)+\cos(a-b))$

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