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$$\displaystyle\underset{m\to +\infty }{\mathop{\lim }}\,\left[ \underset{x\to {{0}^{+}}}{\mathop{\lim }}\,\int_{0}^{x}{{{\left( \underset{n\to \infty }{\mathop{\lim }}\,{{\left( 1-\frac{1}{n} \right)}^{n}} \right)}^{{{t}^{m}}}}t\text{d}t} \right]$$

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Hard to write, easy to solve. – Matemáticos Chibchas Jan 23 '13 at 2:03

1 Answer 1

up vote 2 down vote accepted

$$\underset{n\to \infty }{\mathop{\lim }}\,{{\left( 1-\frac{1}{n} \right)}^{n}}=e^{-1}$$ and $$\underset{x\to {{0}^{+}}}{\mathop{\lim }}\,\int_{0}^{x}{{e^{-t^m}}t\text{d}t}=0,$$ so the answer is $0$.

share|cite|improve this answer brain was locked...:( – Ryan Jan 23 '13 at 2:28

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