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This is a task from an old exam.

Let define:

$V = \text{lin}((1,2,2,1),(1,1,-1,1))$

$W = \cases{x_1-x_2=0\\x_3-x_4 =0}$

$\varphi:\mathbb{R}^{4}\to \mathbb{R}^{4}$ - a symmetrion against V along W.

Please help me calculate $\varphi((1,1,2,0))$

Thanks in advance!

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1 Answer 1

up vote 1 down vote accepted

Let $a:=(1,2,2,1)$, $b:=(1,1,-1,1)$ for $V$ and $c:=(1,1,0,0)$ and $d:=(0,0,1,1)$ for $W$ -- you can check that $W=\mathrm{lin}(c,d)$.

So, we want to decompose the given vector with these: $-b+d=(-1,-1,2,0)$, so add $+2c$ and we're there.

I didn't exactly understand this 'symmetrion against $V$', I guess the directions in $V$ would be reversed and those of $W$ would stay (or the other way around). So, apply $\varphi$ accordingly to $b,c,d$ and use its linearity.

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