# What is wrong with this solution?

$$\ln(x) = 1 + \ln(5)$$

$$x = e^{1+ \ln(5)} = e^{1+5} = e^6$$

What exactly am I doing wrong here?

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it is $e\cdot 5$ not $e^{1+5}$ – user31280 Jan 21 '13 at 20:34

You change $\ln(5)$ to $5$ in the exponent, when it should be $$e^{1+\ln(5)}=e\cdot e^{\ln(5)}=5e.$$
$$\ln x = 1 + \ln 5$$ $$\ln x = \ln e + \ln 5$$ $$\ln x=\ln(5e)$$ $$x=5e$$