Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Possible Duplicate:
How do you integrate $e^{x^2}$?

When I try to integrate (indefinite) $e^{x^2}$, supposing $x^2 = t$, and integrating by parts, the solutions seem to be never-ending. Is there any other way to integrate this?

share|cite|improve this question

marked as duplicate by Martin Sleziak, Nameless, sdcvvc, Stefan Hansen, Gerry Myerson Jan 20 '13 at 10:23

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

up vote 1 down vote accepted

You can use maclaurin series of $e^{x^2}$ to integrate

share|cite|improve this answer

No. It is well-known that there is no elementary antiderivative for $e^{x^2}$.

share|cite|improve this answer
can i know why? And a glimpse of how can it be done in 'advanced' way? – cipher Jan 20 '13 at 9:53
By "elementary", we mean "elementary functions", such as taking powers and multiplying and addition. There is no expression for the integral $e^{x^2}$. We can only give it a name (specfically the "error function"). I don't know how one can prove this. – akkkk Jan 20 '13 at 10:07
@akkkk: The error function is related to the integral of $e^{-x^2}$, not $e^{x^2}$. – Mårten W Jan 20 '13 at 21:06
@MårtenW: I must admit I missed that, but of course this can be solved by some appropriate complex substitution. – akkkk Jan 20 '13 at 21:52

Not the answer you're looking for? Browse other questions tagged or ask your own question.