Show that $p = 3$ and $p = 5$ are the only primes with a maximal $3$ solutions each to $8pq + 1 = a^2$, where $p$ and $q$ are prime.
This isn't true. For example, with $p=11$, you can take $q = 5$ or $q=23$.
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
3 years ago