I know how to use the standard rule
$$p\vee (q\wedge r)\equiv (p\vee q)\wedge (p\vee r)$$
but what if I have a two by two statement like:
$$(p\vee q)\wedge (r\vee s)$$ ...
I'm guessing that it follows a similar rule to the FOIL method in algebra? I took a shot in the dark and came up with this, but I want to make sure my logic is correct.
$$(p\wedge r)\vee (p\wedge s)\vee (q\wedge r)\vee (q\wedge s)$$