Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top


From my current understanding: $K>J$ and $L>K$ , therefore $L>K>J$. How can I compare the first integral $I$ ?

share|cite|improve this question
Hint: $x < e^x$ so $I < \ldots$. – Robert Israel Jan 16 '13 at 4:12
up vote 1 down vote accepted

Robert's hint should answer your question.

I might go about the original problem a different way. Of $J$, $K$, and $L$, there is only one where the antiderivative is easy to compute, and it's easy to see whether that one converges. That observation eliminates several of the 6 alternatives given. Of those remaining, only one is not nonsense (e.g., (f) is nonsense since it deduces convergence from being bigger than something that converges).

share|cite|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.