# The sides of a triangle touch $y^2=4ax$ and two of its angular points lie on $y^2=4b(x+c)$

The sides of a triangle touch $y^2=4ax$ and two of its angular points lie on $y^2=4b(x+c)$. What is the locus of the third angular point?

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A picture might help: I am have probelem imagining sides of a triangle "touching" a parabola. Does this mean tangents? Internal to the triangle? –  Henry Jan 15 '13 at 9:57
$a^2y^2 = 4(2b − a)^2.(ax + 4bc)$ IS IT CORRECT?? –  Pramod Sir Jan 15 '13 at 10:27
Yes. Can you show how u did it pls? –  Ravi Jan 15 '13 at 15:14
And sorry for late reply, i was in tuition... –  Ravi Jan 15 '13 at 15:21