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Hello is there any kind of math that is not based on the concept of 1 but only on continuous expressions? Maybe is this what vector are? If this question is stupid, answer me and I'll erase it.

Thanks!

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You don't have to delete anything, ask away. – Git Gud Jan 13 at 20:42
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Any guess I might have as to what is being asked here would only be a guess. – Michael Hardy Jan 13 at 20:43
Discrete mathematic? – dwarandae Jan 13 at 20:47

closed as not a real question by TMM, Brandon Carter, Davide Giraudo, Alexander Gruber♦, Henry T. Horton Jan 13 at 22:15

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, see the FAQ.

1 Answer

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I don't know if I got you right: With the concept of $1$ you mean that things are or are not?

If that is what you meant then: Yes, it is called Fuzzy Mathematics (based on Fuzzy Logic) where the set of true values is $[0,1]$, or some other ordered lattice. However, this approach is still made from Classic Set Theory.

A fuzzy set on a set $X$ is a function $A:X \rightarrow [0,1]$, so $A(x)$ represents to what degree $x$ is an element of $A$. This covers the usual notion of belonging: If $A(X) \subset \lbrace 0,1 \rbrace$ (i.e. $A$ is a characteristic function) then for an element $x \in X$ either $A(x)=1$ and it is in $A$ or $A(x)=0$ and it isn't.

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Yes maybe it's this , I'm reading the article thanks – Nicolas Manzini Jan 13 at 20:53
Actually i'm bad at math writing i dont understand much of the expression I read (i know it's probably not hard..) but what I seek is maybe more along the idea of math where parameters have only a probability of being defined that is never 1 and never 0. – Nicolas Manzini Jan 13 at 20:59
If I'm solving your questions (which I still don't truly know) then vectors have nothing to do with it. – Zango Lotino Jan 13 at 21:13
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If you want that the probability is never $1$ and never $0$ just think of the lattice $(0,1)$ and carry on with the construction. – Zango Lotino Jan 13 at 21:21

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