Let $f : S^n \rightarrow S^n$ be a continuous map. One can define the degree of $f$ as the integer $k$ such that $f_* : H_n(S^n) \rightarrow H_n(S^n)$ is multiplication by $k$ on $H_n(S^n) \cong \mathbb Z$. However, it also makes sense so define the degree as the integer $k'$ such that $f^*$ is multiplication by $k'$ on $H^n(S^n)$. Must these two integers agree?
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From the universal coefficient theorem for cohomology, we have a natural isomorphism $H^n(S^n)\to\hom(H_n(S^n),\mathbb Z)$. Now write what naturality means for a map $f:S^n\to S^n$, and conclude what you want.