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Today in our physics lecture, our Prof told us during some calculation that for $x\rightarrow0$

$f(x)\rightarrow\frac{1}{x^2}$

which was easily understandable from the context and our previous calculations. However he then continued with the integral

$ \int_0^\infty 4\pi x^2 f(x)\, dx $

and told us that it had had measure $0$ for $x\rightarrow0$. From there one we gave the $x=0$ case a special treatment, since it had physical relevance. My question is now, what does it mean to have a measure of $0$ at some point? Would the intgral

$ \int_0^\infty x\, dx $

have measure 0 at $x=0$? What measure would the integral

$ \int_0^\infty \frac{1}{x}\, dx $

have at $x=0$ and even more, what measure would the integral

$ \int_{y(T)}^\infty \frac{1}{x}\, dx $

have if $y(T)$ is a function approaching zero for $T\rightarrow0$. How do I calculate measure? Although it probably sounds like a homework question, these questions arose during discussions with other students.

Thanks in advance.

share|improve this question
Apparently, your professor was guided by physical understanding of the problem more than by mathematical formalism. Since the former is absent from your question, there is nothing to base an answer on... "can't make bricks without clay". – user53153 Jan 11 at 0:16
So there is no unambigious mathematical concept for a measure at a certain point, given a certain differential? – ftiaronsem Jan 11 at 8:48

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