I want to know how come the function f(y)=1/y is convex?
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migrated from stats.stackexchange.com Jan 9 at 23:56
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One way to check convexity is to check if the second derivative, if it exists, is positive. It is easy to check that the second derivative is positive for $y>0$ in your case. We have $f(y) = \dfrac1y$. Hence, $f'(y) = -\dfrac1{y^2}$, $f''(y) = \dfrac2{y^3} > 0$, for $y>0$. Hence, the function is convex for $y>0$ and concave for $y<0$. |
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