I have been studying for the AP BC Calculus exam (see this previous question) and most of the questions that deal with the first derivative in polar coordinates say that if ${dr\over d\theta}<0$ and $r>0$, then the graph (in polar coordinates) is moving closer to the origin.
What about $r = 4-\theta$, which has $\frac{\mathrm{d}r}{\mathrm{d}\theta} = -1$?
Here is the graph:

Does this disprove the statement?

