Since you have expressed a lack of "rigorous" mathematical background, I'll try to stay simple.
Cauchy sequences are infinite combinations of numbers that get closer together as you go on. It really means that for any distance $\epsilon$>0, we can find a value in the sequence such that all of the remaining values are within $\epsilon$ of any other value.
More technically, there exists an $N$, such that for all $n, m \ge N, |x_n-x_m|<\epsilon$. The absolute value bars being the distance from $x_m$ to $x_ n$, all the later terms fit in an interval around $x_N$ of length $2\epsilon$, and since we can make $\epsilon$ really small, they all bunch up around the limit. The limit doesn't need to exist, it is just the "value" for which they all clump around. Now to the problem at hand.
We now see that the max and min functions, as we have defined them, work. Let's look at $max(x_n, y_n)$, Then since $x_n \to x$ and $y_n \to y$, so $max(x_n, y_n)\to max(x, y)$. Since large values of our "max sequence" have arguments really close to the limits, the value is close to the limit.
To see this, take $\epsilon$>0, and take $N=max(N', N'')$, where $N'$ is the value for $x$ and $N''$ for $y$ for $\epsilon$. Then the max has bunched itself in a little interval for values greater then $N$. Since $\epsilon$ can be as small as we like, we have shown that it clumps up around the limit.
Convergence and the idea of getting arbitrary close are closely tied concepts mathematics. Your definition works for any converging sequence, which is implied by the limits.
A good book if you don't have much experience in mathematics is Rosenlicht's, "Introduction to Analysis". It's not really in your field, but it's short and well written. It will give you some fundamental mathematics, some convergence and topology, and then rigorous limits, continuity, and calculus.
max([2, 1.7, 1.24, 0.8], [5, 1.5, 1.04, 0.6]), wouldn't the answer (by the method I gave above) be[5, 1.7, 1.24, 0.8]? A number larger than either individual number. Not approachingx+yI agree, but still... – Karl Barker Jan 7 at 16:47