Sign up ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Is $$\lim_{n \to \infty} x^n $$ a continuous function on [0,1]?

PS: The original question was for $\lim_{n \to \infty} (\sin(x))^n $ but it brought it complications that are not relevant to the main idea.

share|cite|improve this question
This function does not defiened at $x=(2n+3/2)\pi$ for all $n\in\mathbb{Z}$. – Hanul Jeon Jan 6 '13 at 7:24
What is the domain over which you are interested in continuity? Is it the entire $\mathbb{R}$? – user17762 Jan 6 '13 at 7:24
If you add an absolute value sign, the function still remains discontinous – Amr Jan 6 '13 at 7:25
Arjang: The purpose of this homework is to make you identify the limit pointwise. That is, fix $x$, does the limit exist and what is it? – Did Jan 6 '13 at 7:27
Thanks for the explanations, unfortunately I fail to see the relevance of this question for the two others, nor the other way round. (If the problem is to find properties which fail to be automatically satisfied when one passes to the limit (whatever that means), try this: every integer $n$ is finite; let $n\to\infty$; then...) Anyway. – Did Jan 6 '13 at 11:33

1 Answer 1

up vote 2 down vote accepted

Answering the two questions below, should enable you to conclude on the continuity of the function.

What is $\lim_{n \to \infty}1^n$?

What is $\lim_{n \to \infty}a^n$ for $a \in [0,1)$?

share|cite|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.