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Given a set of n points is it always possible to construct a non self intersecting polygon?

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Closed polygon with these as only vertices? We need conditions, take $n$ collinear points. – André Nicolas Jan 5 at 6:39
Polygon that does what? – Alex Becker Jan 5 at 6:40
@AndréNicolas I want to know given any random non collinear points is it always possible to construct a non self-intersecting closed polygon. – harish.venkat Jan 5 at 6:56
An obviously necessary and sufficient condition is that the set of points be "non-reentrant", i.e. no point is inside the convex hull of the other points. – Ewan Delanoy Jan 5 at 7:01
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@EwanDelanoy Why is this necessary? The polygon only needs to be simple, not convex. – Erick Wong Jan 5 at 7:15
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1 Answer

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Choose a point $x_0$ of your set and order the other points around $x_0$ counter-clockwise. Label them $x_1,x_2,\ldots x_{n-1}$ according to that order. You get a non intersecting polygon and $x_0$ is in its kernel.

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