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If you define a polygon - say, for simplicity, a triangle - as a list of functions, defined piecewise, for example:

  • $a(x)=2x$ defined on $[0,1]$
  • $b(x)=-2x+2$ defined on $[1,2]$
  • $c(x)=0$ defined on $[0,2]$

What do you get by deriving the functions on their intervals and plotting $a'(x)$, $b'(x)$ and $c'(x)$? (In this specific case, the result is made of three segments parallel to the x axis, but what is the result of any given polygon?)

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it will just be lines parallel to $x-axis$ in the given intergal . –  Theorem Jan 2 '13 at 11:56
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Nothing interesting, it heavily depends on the parametrization you give. –  Najib Idrissi Jan 2 '13 at 12:00

1 Answer 1

up vote 1 down vote accepted

$(ax+b)' = a$, thus if you define a set of line segments as you did, their derivatives will be defined as $y = a_i$ for $x \in [p_i, q_i]$ (here $a$ comes from the line equation and $[p, q]$ is the interval on which it is defined). These lines have a property that $\sum a_i|p_i - q_i| = 0$.

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