Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

This problem is as titled.

The textbook states that the order of the Weyl group of type $E_8$, $F_4$ are $2^{14}3^55^27$ and 1152 respectively, but I am wondering how are these groups like, namely, how can they be decomposed into simpler groups, or what kind of subgroup or ideals do they have.

Thanks for any attention and help~

share|improve this question
1  
In the title you also ask about $G_2$: but that one is easy... The Weyl group $W(G_2)$ is simply a dihedral group of order $12$. –  Mariano Suárez-Alvarez Mar 13 '11 at 19:26

2 Answers 2

up vote 3 down vote accepted

According to GAP, $F_4$ is

(((((C2 x D8) : C2) : C3) : C3) : C2) : C2

Here C2 and so on denote cyclic groups, D8 denotes the dihedral group of order $8$, x denotes direct product, and : denotes semidirect product. That is not the most enlightening description of the group, but shows that it is made up from rather simple pieces.

You should download GAP and play with it a lit to explore the subgroups and what not in the groups. It's fun.

share|improve this answer

Every Weyl group is a Coxeter group with Coxeter diagram given more or less by the Dynkin diagram of the corresponding Lie algebra (up to some minor alterations). A good reference is Humphreys' Reflection groups and Coxeter groups.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.