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I am currently working on this problem:

Let $$P(x) = x^4+x^3+x^2+x+1$$ show that there is an extension $K$ of $\mathbb Q$ with $[ K : \mathbb Q ] = 4$ over which $P(x)$ splits into linear factors.

I know I just need to find the roots in $\mathbb C$ or $\mathbb R$ and adjoin them to $\mathbb Q$ to create the field over which it can split. I just can't seem to find any roots without using a calculator, and that just leaves me with decimal solutions. It seems if I had a nice solution in radicals it would be easy to find the necessary extensions. So I was wondering if this polynomial had simple solutions in radicals. Also, should I know how to solve equations like this without a calculator?

Thanks

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This shoudn't be so hard if you know that this polynomial is irreducible (why?) over $\mathbb Q$ and noticing that $P(X)=\frac{X^5-1}{X-1}$. – YACP Dec 30 '12 at 9:43

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