# Blaschke Factor mapping holomorphic

In Stein and Shakarchi's book, Chapter 1, Exercise 7 asks us to show that $$\left|\frac{w-z}{1-\overline{w}{z}}\right|<1$$ if $|z|<1$ and $|w|<1$, with equality if either $|z|=1$ or $|w|=1$. I was able to show this much, and for the second part of the question, most of it is immediate from the above, except showing that for a fixed $w\in\mathbb{D}=\{z\in\mathbb{C}:|z|<1\}$ $$F(z)=\frac{w-z}{1-\overline{w}{z}}$$ is holomorphic. I can do it if I completely expand everything and get it to the form $F(x,y)=u(x,y)+iv(x,y)$ (I haven't actually written everything out, only assured myself that I could actually get it to such a form). From here I should be able to check the Cauchy-Riemann equations and verify the partial derivatives are continuous, which is enough to show that $F$ is holomorphic, but I was wondering if there was a better/more elegant way of showing it? Thanks!

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Quotients of holomorphic functions are holomorphic where they're defined. – Jesse Madnick Dec 28 '12 at 5:30
What is the definition of holomorphic that you're using? – Jonas Meyer Dec 28 '12 at 5:37
@JonasMeyer: The limit definition (mimics the definition of a derivative for real variables). – anon271828 Dec 28 '12 at 5:44
@anon271828: That isn't quite an answer to my question, but I take it you mean that a function is defined to be holomorphic if it is everywhere (complex) differentiable? Sometimes continuity of the derivative is also assumed (although it is redundant). In calculus, you know how to find the derivative of $f(x)=\dfrac{3-x}{1-3x}$? I just want to point out that this is very similar. – Jonas Meyer Dec 28 '12 at 5:49