Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Can you please help me?

The line $-4x-2y+14=0$ slopes to graph of function $f(x)=x^3-x^2+4x$. Find point of slope...

I don't really understand how to solve this question. Thanks.

share|improve this question
    
Thanks! Yes it seems like the question is not correct –  Tina Dec 26 '12 at 11:13

1 Answer 1

up vote 1 down vote accepted

Hint: Your line is $$y=-2x+7$$ That line is a slopes the graph of the differentiable function $f$ if and only if there exists a point $x_0\in D_f$ so that $f^{\prime}(x_0)=-2$ (can you see where $-2$ comes from?) and $y=f(x_0)$. That $x_0$ is your point of slope. You shall end up with a system of equations that has no solutions... and so the problem is wrong

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.