# Simple Probability Question…

I posted a similar probability question before but I realized I missed something, so here's another question for you folks.

Say, I have a set of $10,000$ numbers which, if chosen $10,000$ times, have a probability of $\frac{1}{3.3}$. Some numbers may have a probability of $\frac{1}{4}$ some $\frac{1}{2}$ some $\frac{1}{5}$ but the total of all 10,000 numbers will be $\frac{1}{3.3}$. So if I do $30.3$ thousands draws I will win $\frac{1}{3.3}$ times.

Now say, $2500$ numbers of those $10,000$ numbers has a probability of $\frac{1}{5.3}$.

Now, in order for the other all these $10,000$ numbers to have a total probability of $\frac{1}{3.3}$, the other $75000$ must have a probability of less than $\frac{1}{3.3}$, otherwise the total wouldn't equal $\frac{1}{3.3}$.

How do I calculate the probability of the other $7,500$ numbers?

Thanks

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What do you mean by "A set of 10.000 numbers have a probability of 1/3.3" ? –  MSKfdaswplwq Dec 24 '12 at 13:24

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