Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I want to know if the sum $$\sum_{n=1}^\infty\frac{\sqrt{n+1}-\sqrt{n}}{n}$$ converges or not. I've tried the ratio and root test but they don't fit. So wolframalpha says that the sum converges by the comparison test. So I've tried to find a convergent majorizing sum (I've tried e.g. $\sum\frac1{n^\alpha}$ with $\alpha>1$ etc.) but I can't find one.

does anybody know one?

share|improve this question

1 Answer 1

up vote 10 down vote accepted

$$\frac{\sqrt{n+1}-\sqrt n}{n}=\frac{1}{n(\sqrt{n+1}+\sqrt n)}<n^{-\frac32}$$

share|improve this answer
2  
Note that between the first and second steps there's an implicit 'clearing of the numerator' by multiplying by $\dfrac{\sqrt{n+1}+\sqrt{n}}{\sqrt{n+1}+\sqrt{n}}$ and then using $\left(\sqrt{n+1}+\sqrt{n}\right)\cdot\left(\sqrt{n+1}-\sqrt{n}\right) = \left(\sqrt{n+1}\right)^2-\left(\sqrt{n}\right)^2=n+1-n=1$. –  Steven Stadnicki Dec 19 '12 at 17:22

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.