This is an exercise from a probability textbook: A frazzle is equally likely to contain $0,1,2,3$ defects. No frazzle has more than three defects. The cash price of each frazzle is set at \$ $10-K^2$, where $K$ is the number of defects in it. Gummed labels, each representing $\$ 1$, are placed on each frazzle to indicate its price. What is the probability that a randomy selected label will end up on a frazzle which has exactly two defects?
Since the frazzles are equally likely to have $0,1,2,3$ defects, I may argue that a label is equally likely to appear on any of them. On the other hand, frazzles with less defects are more expensive, therefore requiring more labels, from this perspective, a label is most likely to appear on a frazzle with no defects. I am confused here.