# Geometric transformation on circle equation

Suppose that I have variables $x_1,x_2$ and following circle equation: $x_1^2+x_2^2=1$. Now I have a matrix $A$ which will be used to transform my circle equation. $Z=AX$ where $X$ is a vector with $x_1,x_2$ and $A$ is the transformation matrix. What will the final circle look like and how can I compute its equation? (The final shape can be an ellipsoid).

-
Do you mean $x_1^2+x_2^2=1$? – David Mitra Dec 14 '12 at 1:05
As you wrote it, that equation is just $\,x_1+x_2=1\,$. This is not a circle unless you're working within a very weird geometry. – DonAntonio Dec 14 '12 at 1:05
Ok I am sorry about that! I meant $x_1^2+x_2^2=1$ – nikosdi Dec 14 '12 at 1:36

## 1 Answer

You can parametrize your circle as:

$$x_1 = \cos(t)$$ $$x_2 = \sin(t)$$

for $0\leq t < 2\pi$. The column vector for a point at a given value of $t$ is: $$\mathbf{x}(t) = \left(\begin{array}{c} \cos(t) \\ \sin(t) \end{array}\right)$$ again for any $0\leq t < 2\pi$.

For matrix $A = [ a_{ij} ]$, the image of all points $\mathbf{x}(t)$ can be written:

$$A\mathbf{x}(t) = \left( \begin{array}{cc} a_{11} & a_{12} \\ a_{21} & a_{22}\end{array}\right)\left(\begin{array}{c} \cos(t) \\ \sin(t) \end{array}\right)$$

The resulting set of points can be parametrized as $x_1 = a_{11}\cos(t) + a_{12}\sin(t)$ and $x_2 = a_{21} \cos(t) + a_{22} \sin{t}$. This is an explicit equation for the image of the circle under $A$.

However, it doesn't really illustrate what happens geometrically. What kind of things can a matrix $A$ do to a shape in the plane? It can do any combination of rotating, scaling, shearing, reflection, and projection. Maybe you can convince yourself that applying any of the first four to a circle yields an ellipse. However, if the matrix represents a projection transformation, the image of the circle will be a line segment. I'm sure you can demonstrate all of these things algebraically, but it might be more rewarding to graph a few examples.

-
Thank you for your time!I understand what you explained to me very clearly.Ok I need to do some experiments because the question wasn't "really" about geometry.I was trying to understand the effect that a transformation will have. – nikosdi Dec 14 '12 at 2:55