Solving a quadratic inequality
Suppose we have $(x-5)(x+2) > 0$. Can we solve it like this: $(x-5) > 0$ and $(x+2) >0$, $x > 5$ and $x > -2$? Please help.
If $ab>0$ does it always imply that $a>0$ or $b>0$. You can also have both $a$ and $b$ to be less than $0$. So in your question it can also be $(x-5)<0$ along with $(x+2)<0$.