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Suppose $ F(x)=f(g(x)) $

  • $g(1)=3$
  • $g'(1)=4$
  • $f'(1)=6$
  • $f'(3)=5$

What is $F'(1)$ ?

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use chain rule.. – user127.0.0.1 Dec 7 '12 at 0:52
up vote 3 down vote accepted

Hint: By the Chain Rule, $F'(x)=g'(x)f'(g(x))$. Now use the information provided to evaluate the various bits when $x=1$.

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This was the hint I needed, thank you! – EngGenie Dec 7 '12 at 0:55

$F(x)=f(g(x))$, so $F'(x)=f'(g(x))g'(x)$ and for $x=1$ it is $F'(1)=f'(g(1))g'(1)=f'(3)g'(1)=5\cdot4=20$

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$$F'(x) = f'(g(x))\cdot g'(x)$$ $$F'(1) = f'(g(1))\cdot g'(1) = f'(3)\cdot 4 = 5 \cdot 4 = 20$$

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