I'm assuming you refer to Macaulay2 (Macaulay is an older version, not much used today).
The following code gives the radical of your ideal:
R = QQ[u,v,a,b]
I = ideal (u^2*v-a^3,u*v^2-b^3,u*v-a*b)
radI = radical I
So, according to Macaulay2, we have $\sqrt{I} = (a^2-ub,va-b^2,uv-ab)$.
Beware, computing radicals can be extremely slow if you have many generators, because the algorithm must compute a Gröbner basis first. However, in this case, the ideal is binomial, and there are extremely efficient algorithms for computing with binomial ideals. (in Macaulay2, the package "BinomialIdeals" does this).
Some (two) references on how to learn Macaulay2: