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Let $\mathcal L$ be a language with only a binary predicate $E$, and let $T$ be a theory of structures in which $E$ is an equivalence relation which partitions the structure into two infinite sections. It is easy to see that $T$ is $\aleph_0$-categorical but not $\aleph_\alpha$-categorical when $\alpha>0$.

My question: can there be a $\kappa \not \le \aleph_0$ such that $T$ has a model of cardinality $\kappa$ and is $\kappa$-categorical? What about $\kappa$ is infinite but Dedekind-finite?

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@ChrisEagle Yes, thank you. –  Popopo Nov 28 '12 at 16:16
    
By $\kappa$-categorical, do you mean $T$ has (up to isomorphism) exactly one model of cardinality $\kappa$, or at most one? If $\kappa$ is amorphous, $T$ has no models of cardinality $\kappa$ at all. –  Chris Eagle Nov 28 '12 at 16:17
    
@ChrisEagle Yes, I have corrected my post. –  Popopo Nov 28 '12 at 16:19
    
@AsafKaragila Okay, thanks to you. –  Popopo Nov 28 '12 at 16:36

1 Answer 1

up vote 4 down vote accepted

If $M$ is a model of $T$ let $M_0$ and $M_1$ denote the two parts defined by $E$.

Suppose that $A$ is an infinite Dedekind-finite set. If $A$ is amorphous then it cannot be a model of $T$ to begin with because it cannot be split into two infinite sets.

Suppose that $A$ can be split into $A_0$ and $A_1$. If $|A_0|=|A_1|+\frak a$ for $\frak a$ nonzero, then taking any $B\subseteq A_0$ such that $0<|B|<\frak a$ defines a non-isomorphic model by $A'_0=A_0\setminus B$ and $A'_1=A_1\cup B$. To see that this partition is not isomorphic to the previous partition note that it could only happen if $|A'_1|=|A_0|$ (because we remove points from $A_0$ and its cardinality is strictly smaller now) but this means there is a bijection $f\colon A_0\to A_1\cup B$ which is false because $|A_0|=|A_1|+|B|=|A_1|+\frak a$ and therefore $|B|=\frak a$, in contradiction to the way we chose $B$.

If $A$ can be split into two incomparable parts, then any exchange of points will keep it incomparable by a similar argument.


However it is possible to get categoricity in $\aleph_1$-amorphous cardinals. Namely cardinals of sets that cannot be split into two disjoint uncountable sets.

Suppose that $A$ is $\aleph_1$-amorphous, and it has no infinite Dedekind-finite subset, then any partition of $A$ into two parts would have to have one part of size $\aleph_0$ and another part of size $|A|$. Therefore categoricity follows for any $\aleph_1$-amorphous cardinal.


Examining this proof shows that $T$ is categorical in $\kappa$ if and only whenever $\kappa=\frak a+b$ then we can guarantee that either $\frak a$ or $\frak b$ is $\aleph_0$, and the other is Dedekind-infinite.

This happens if and only if $A$ cannot be split into two uncountable sets, has no infinite Dedekind-finite subsets, and if $B\subseteq A$ is infinite then $|B|=|A|$ or $|B|=\aleph_0$.

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I have to admit that I wrote my initial comment with an elaborate idea I had in mind, but as the details began to unfold it became increasingly difficult to prove, and I decided to pick a simpler example for now. If I finish the proof I will definitely post it. –  Asaf Karagila Nov 28 '12 at 18:17
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I am under the impression that OP meant to ask about models of this particular theory. –  tomasz Nov 29 '12 at 14:09
    
@tomasz: You know... I think you're right. :-) Let me modify my answer to address the actual question! Thanks!! –  Asaf Karagila Nov 29 '12 at 14:10
    
Er...I'm not sure. Assume $\kappa=\lambda+\aleph_0$ be an $\aleph_1$-amorphous cardinal. It is Dedekind-infinite, but Does it exist some cases $\lambda<\kappa$? –  Popopo Dec 1 '12 at 14:07
    
@Popopo: If $\kappa$ is $\aleph_1$-amorphous then $\lambda=\kappa$. –  Asaf Karagila Dec 1 '12 at 14:12

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