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I have to solve the following,

$$\int \frac{8\sin(2x)}{\sin(x)}dx$$

but I'm not sure where to begin. I thought of the anti derivative been something like -4cos(2x) but that doesn't take care of the sin in the denominator. Thanks ahead of time.

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Do you know an identity involving $\sin2x$? –  Gerry Myerson Nov 28 '12 at 6:20
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up vote 3 down vote accepted

Hint: You can use the following trigonometric identity: $$\sin(2x) = 2\sin(x)\cos(x)$$

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