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Do integral transforms with meromorphic kernels always have analytic continuation ? I think so, but I do not know how to prove it.

For clarity with analytic continuation I assume it was already analytic somewhere.

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By "meromorphic kernel with analytic continuation" do you mean "meromorphic kernel on all of $\mathbb{C}$"? –  robjohn Nov 27 '12 at 22:51
    
Yes thats what I mean. –  mick Nov 27 '12 at 23:00
    
Mick? Are you okay? I had no other way to contact you and I noticed you disappeared from the chat, I felt responsible for this - due to my joke. If this was the reason, I was only kidding, sorry if it hurt you. –  Vÿska Dec 6 '12 at 12:53
    
@GustavoBandeira Dont worry my friend. I do not even know what you are talking about :) –  mick Dec 29 '12 at 20:05

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