Given parametric curve: $x=t\cos(t)$, $y=t^2$, how can i rotate the curve about the origin by an angle $\theta=\pi/3$?
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In $x,y$ coordinates, counterclockwise rotation by $\theta$ takes $(x,y)$ to $(u,v) = (x \cos(\theta) - y \sin(\theta), x \sin(\theta) + y \cos(\theta))$.