# Rotating parametric curve

Given parametric curve: $x=t\cos(t)$, $y=t^2$, how can i rotate the curve about the origin by an angle $\theta=\pi/3$?

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Converting to polar coordinates seems natural. –  icurays1 Nov 27 '12 at 19:11

In $x,y$ coordinates, counterclockwise rotation by $\theta$ takes $(x,y)$ to $(u,v) = (x \cos(\theta) - y \sin(\theta), x \sin(\theta) + y \cos(\theta))$.
Just plug in the parametric expressions for $x$ and $y$ and you have parametric expressions for $u$ and $v$.