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marked as duplicate by Qiaochu Yuan Mar 7 '11 at 12:04

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

fairly sure there was a duplicate of this question... – InterestedGuest Mar 2 '11 at 0:18
There might be. That's what I thought and tried to find it (put very little effort) but couldn't. – Sunil Mar 2 '11 at 0:20
@InterestedQuest, @Sunil This was the dupe: – Uticensis Mar 7 '11 at 11:24
up vote 9 down vote accepted

If you count carefully, you'll see that the base is meant to be $13$ units long, while the height is $5$ units long. That means that the triangle on the top on the top figure, which has a height of $2$, should have a base of length $b$, where $$\frac{b}{2} = \frac{13}{5}$$ or $b = \frac{26}{5}$, longer than the $5$ units depicted.

Likewise, the bottom red triangle, with a base of size $8$ should have a height of length $h$, with $$\frac{h}{8} = \frac{5}{13}$$ or $h = \frac{40}{13}$, which is a little longer than the $3$ depicted.

So in fact, the "missing square" comes from misdrawing the pictures (or from having the individual figures drawn correctly, but the composed figures not being real triangles; the two inner triangles are not similar, though they "should" be).

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Eye trick! Look at the angles formed where the red and green triangle meet.

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Looking at angles may not be enough given the thick lines. But the slope of the hypotenuse of the red triangle is $3/8 = 0.375$ while the slope for the green triangle is $2/5 = 0.4$. If the whole thing was a triangle (which it is not) then the slope would be $5/13 =0.3846\ldots$ – Henry Mar 1 '11 at 23:41
Indeed the thick lines are what make the "angles different" - and which is what makes it sloppy. – milcak Mar 1 '11 at 23:47

It isn't true. See the Wikipedia page about this puzzle.

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Take your credit card, driver's license, or some other readily available straightedge and put it against the hypotenuse. You'll find the composite shape is not a triangle, but a cleverly disguised irregular quadrilateral. The better, more mathy answers made sense once I got my brain away from the idea that there were triangles involved.

Nothing but a cheap trick designed to confound.

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