# Can $0$ be viewed as an operator, somehow related to derivatives? [closed]

Isn't zero an operator that transform every thing to himself so division by this operator is null, which is why division by zero is undefined?

Something like derivative but special one. $$0=\frac {d}{d(\text{something})}$$ $$0*1=\frac {d 1}{d(\text{something})}=0$$ $$\frac {1}{0}=\frac{1}{\frac {d}{d(\text{something})}}=\text{null.}$$

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possible duplicate of Division by $0$ – Austin Mohr Nov 25 '12 at 10:13
What's the question? – Rahul Narain Nov 25 '12 at 10:16
@FrenzY DT. good edit – Neo Nov 28 '12 at 13:06

## closed as not a real question by Austin Mohr, Hans Lundmark, J. M., Asaf Karagila, DidNov 25 '12 at 12:21

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, see the FAQ.

Usually $0$ is viewed as a number, not an operator. An operator would be addition, division, multiplication etc. Most axiomatic approaches to numbers introduce $0$ by asserting that $x+0=x$, in general; the purpose of this number is that we can then define the additive inverse of a number $x$ as the (provably unique) $y$ such that $x+y=0$.