# Finding general solution of differential equation.

How general solution of this form of differential equation can be found? $$\frac {dy}{dx} = \frac {2y}{x}$$

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$$\frac{dy}{dx}=\frac{2y}{x} \hspace{10pt}\Leftrightarrow \hspace{10pt}\frac{dy}{2y}=\frac{dx}{x}$$ Now you just need to integrate.
okay that becomes $$\frac {y^2}{4}dy = \log xdx$$ am i right? – TPSstar Nov 23 '12 at 17:28
No, That becomes $\frac12\ln y=\ln x+C$ and so $y=Cx^2$ – Dennis Gulko Nov 23 '12 at 17:32