I came across this problem which says:
Let $G$ be a group of order $60$.Pick out the true statements:
(a)$\,G$ is abelian,
(b)$\,G$ has a subgroup of order $30,$
(c)$\,G$ has subgroups of order $2,3$ and $5,$
(d)$\,G$ has subgroups of order $6,10$ and $15.$
To tackle the problem,i have used Sylow's first theorem and concluded that G has subgroups of order $2,3$ and $5.$ But i do not know how to determine whether G is abelian or not. Please help.