I had this show up in a problem and I went completely blank. How do I compute
$$\int a^t \mathrm{d}t$$
where $a$ is some constant?
|
I had this show up in a problem and I went completely blank. How do I compute $$\int a^t \mathrm{d}t$$ where $a$ is some constant? |
|||||||||||
|
|
$a^t = e^{t \ln a}$. From there, $\int a^t dt = \int e^{t \ln a} dt$, which is trivial to integrate. The answer is $$\frac{a^t}{\ln a} + k$$ |
||||
|
|
|
Note that $a^t = (e^{\log(a)})^t = e^{t \log (a)}$ and $$\int e^{bt} dt = \dfrac{e^{bt}}{b} + \text{ constant}$$ |
|||
|
|
|
Since $\dfrac{\text{d}}{\text{dt}} a^t=a^t\ln(a),$ we have $$\int a^t \text{dt}=\dfrac{a^t}{\ln(a)}+C$$ |
|||
|
|
|
$$\int a^tdt=1/\log(a) \cdot \int a^t \log(a)dt=a^t/ \log(a)+C$$ This is because the derivative of $a^t$ is $a^t \log(a)$ . |
|||||
|