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How do you calculate the following summation? $\sum_{i=k}^n i$

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3 Answers 3

This is a special case for the formula for the sum of n terms in an arithmetic progression:


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Thanks. I probably should have specified that I was looking for a direct formula or derivation. –  credford Aug 13 '10 at 22:01

$\sum_{i=k}^n i = \sum_{i=0}^n i - \sum_{i=0}^{k-1} i = \frac{1}{2} \left[ n(n+1) - (k-1)k \right]$

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up vote 1 down vote accepted

Okay. I was able to find it here, thanks.


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