# Probability conditioned on disjunction of events

This seems elementary, but I cannot see a quick proof:

For events $A, B, C$ we have $$P(A \mid B \cup C) \leq \max(P(A \mid B), P(A \mid C))$$

Is this right?

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## 1 Answer

It is incorrect. Consider this counter-example: $A=\{1,2\}$, $B=\{1,3\}$, $C=\{2,3\}$ and $P(\{1\})=P(\{2\})=P(\{3\})=\frac{1}{3}$.

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