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How this language is Context free?

$\mathcal{L2}=\{a^ib^jc^i \;|\;i,j\geq 1\}$ Please explain me.

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1 Answer 1

$$S\to a A c$$ $$A\to a A c$$ $$A\to bB$$ $$B\to bB$$ $$B\to \epsilon$$

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Is this language CFL? –  Sudhir Nov 14 '12 at 17:25
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@sudhir: The answer contains a context-free grammar which generates your language, so yes. –  Tara B Nov 14 '12 at 17:28

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