# Missing exponent?

$\frac{256}{2^S}=64$

How would you solve for S?

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FURTHER HINT: $\mathrm{log}_2(2^{x}) = x$
Hint: $256=2^8$, $64=2^6$, and remember the rule $2^x/2^y = 2^{x-y}$.
Another hint: $256/64 = 2^S$ –  Henry Feb 25 '11 at 9:40