If $X$ follows $\chi^2_5$, determine the constants $c$ and $d$ so that $P(c < X < d) = 0.95$ and $P(X < c) = 0.025$. $\chi^2$ is chi-squared distribution
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the easiest way is to use R(qchisq). But I think you shoud do it yourself. Notice that chisq is the square sum of standard normal. $\chi_1^2=x^2, x \leadsto n(0,1)$. so in your case, it is $Y=\sum x_i, i=1,2,3,4,5$. where $Y$ has normal (0,5)