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$ \frac{\partial}{\partial s} \left(\frac{\partial u}{\partial x}\right) \frac{\partial x}{\partial s}$

$\frac{\partial u}{\partial x}\frac{\partial}{\partial s}\left(\frac{\partial x}{\partial s}\right) $

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This looks like homework. What have you tried? – espen180 Nov 11 '12 at 22:56
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Isn't it just $\frac{\partial}{\partial s} \left(\frac{\partial u}{\partial x}\right) \frac{\partial x}{\partial s}-\frac{\partial u}{\partial x}\frac{\partial}{\partial s}\left(\frac{\partial x}{\partial s}\right)$? – Ross Millikan Nov 11 '12 at 23:09
@RossMillikan. I'm not sure if he is using "difference" to mean subtraction or distinction. – Inquest Nov 11 '12 at 23:18
it's not really homework. i am just trying to understand what those terms really mean. – question Nov 11 '12 at 23:23
by difference i meant distinction – question Nov 11 '12 at 23:24
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