Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

At $8am$ particle $A$ is at point $(0,0)$ and moves horizontally to the right with constant velocity of $60km/h$. At the same time particle $B$ is at the point $(0, A+B+C+5)$ and moves horizontally to the left with a velocity of $30km/h$. what are the rates of change of the distance between the two particles at $8.00am, 9.00am$? and in general time $t$?

share|cite|improve this question
$A$ and $B$ are names of particles, but then you add them as if they are numbers. What does that mean? And what's $C$? – littleO Nov 11 '12 at 11:08

let distance between cars be z



at time t the cars are moved a distance of




$z'(t)=\frac{1}{z}(90(t)+0)$ where


share|cite|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.