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In an exercise asking to mark true or false, it shows:


It really look like false to me. But the answer is true! How can it be?

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which books is this from? – shuhalo Feb 24 '11 at 2:37
up vote 3 down vote accepted

Suppose $x\neq 0$, and $a\neq b$. Multiplying top and bottom of the left hand side by $x$ shows $$\frac{1}{a/x-b/x}=\frac{x}{a-b}$$ and this equals $\frac{1}{a-b}$ if and only if $x=1$.

In short, it can't be true, but my guess is that the book meant to have an $x$ as the numerator of the right hand side of the original equation.

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it really looks like the book's mistake.. – Tom Brito Feb 23 '11 at 23:57
I edited to indicate that. Even books make mistakes from time to time. – Eric Naslund Feb 24 '11 at 0:00
One could also point out that they are not strictly equal-the RHS is defined at x=0, while the LHS is not – Ross Millikan Feb 24 '11 at 14:42

Are you sure it is not $\frac{1}{a/x-b/x}=\frac{x}{a-b}$? Otherwise I agree with you.

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$\frac{1}{\frac{a}{x}-\frac{b}{x}} = \frac{1}{\frac{a-b}{x}} = \frac{x}{a-b} \not\equiv \frac{1}{a-b}$

So this is not true in the general case.

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