Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

This question already has an answer here:

Suppose that $R = S × T$ is a direct product of rings with $S$ and $T$ each having at least two elements. Prove that $R$ has zero divisors.

share|cite|improve this question

marked as duplicate by rschwieb abstract-algebra Jan 6 '15 at 21:55

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

(0,1)(1,0)=(0,0). – anon Nov 9 '12 at 3:13
The key is $1\ne 0$ because both $|S|$ and $|T|$ are at least 2. – peoplepower Nov 9 '12 at 3:16
up vote 3 down vote accepted

For any $a\ne 0$, $(a,0)\cdot (0,a)=(0,0)$.

share|cite|improve this answer

Hmmm...what about the elements $\,(1,0)\,\,,\,\,(0,1)\,$?

Of course if one, or both, of the rings have no unit you can choose any non-zero elements instead of $\,1\,$

share|cite|improve this answer

What does it mean for $R$ to have zero divisors? That means it has nonzero elements that multiply to zero. How do you write elements of $R$? as ordered pairs of elements from $S$ and $T$.

So you are asking if there are any non-zero solutions to

$$ (s_1, t_1) (s_2, t_2) = (0, 0) $$

such that $(s_1, t_1) \neq (0,0)$ and $(s_2, t_2) \neq (0,0)$.

That is, you want to find values $s_1, s_2 \in S$ and $t_1, t_2 \in T$ such that all of the following hold:

  • $s_1 s_2 = 0$
  • $t_1 t_2 = 0$
  • Either $s_1 \neq 0$, $t_1 \neq 0$, or both
  • Either $s_2 \neq 0$, $t_2 \neq 0$, or both.

Now, solve!

share|cite|improve this answer

Not the answer you're looking for? Browse other questions tagged or ask your own question.