Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

For the language L = $\{\Sigma^*. 0 .\Sigma^5 . 1. \Sigma^*\}$

The NFA must have 8 states. Also, what would be the upper bound on the number of states of a DFA recognizing L.

enter image description here

share|improve this question
1  
The NFA looks good, though you should have said that $\Sigma=\{0,1\}$. There is no upper bound on the number of states of a DFA recognizing $L$; did you mean lower bound? –  Brian M. Scott Nov 8 '12 at 7:50

1 Answer 1

Delete the $\lambda$-edge from $q_1$ to $q_8$. Presently the automaton accepts every string over $\{0,1\}$.

In your question delete the set-brackets in $\{ \Sigma^* \cdots\Sigma^* \}$. In itself, $\Sigma^*$ is a set (of strings), so it is not necessary (in fact wrong) to add another `level' of sets.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.